-2x^2+60x-250=0

Solution for -2x^2+60x-250=0 equation:

-2x^2+60x-250=0

a = -2; b = 60; c = -250;
Δ = b2-4ac
Δ = 602-4·(-2)·(-250)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-40}{2*-2}=\frac{-100}{-4}
=+25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+40}{2*-2}=\frac{-20}{-4}
=+5
$